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LO 2.3.1Calculate the dot product of two given vectorsgeometry
A child pulls a wagon by its handle, at an angle to the ground.
Split the pull: along the motion and straight up.
The wagon moves along the ground …
… so only the part along the motion does work.
LO 2.3.1Calculate the dot product of two given vectorsalgebra
| product | |||
|---|---|---|---|
| 3 | −1 | −3 | |
| 5 | 3 | 15 | |
| 2 | 0 | 0 | |
| add | 12 | ||
Example 2.21: Find (a) and (b) .
(a) 12
(b) 18
Angle between Two VectorsalgebraExample 2.26 · vectors as lists
| invitations | party favors | decorations | food service | |
|---|---|---|---|---|
| price | 2.50 | 1.50 | 4.50 | 1.25 |
| cost | 0.25 | 0.25 | 0.50 | 0.20 |
| quantity | 1258 | 342 | 2426 | 1354 |
Sales $16,267.50; cost $1,883.80
Profit $14,383.70
Favors now $2, invitations cost 10¢; sold 1408, 147, 2112, 1894.
Sales $15,685.50; profit $14,073.15
LO 2.3.1Calculate the dot product of two given vectorsalgebraTheorem 2.3
| Property | Rule | |
|---|---|---|
| i | commutative | |
| ii | distributive | |
| iii | associative (with a scalar) | |
| iv | property of magnitude |
No associative law for three vectors: means nothing — is already a number.
The Dot Product and Its PropertiesalgebraExample 2.22
Example 2.22: . Find , , .
(a)
(b) −12
(c) 20
. Find and .
;
The Dot Product and Its Propertiesalgebraproof · Theorem 2.3
i; commutative
iii; associative
iv; magnitude
LO 2.3.2Determine whether two given vectors are perpendicularbridgeTheorem 2.4
Drag the head of ; compute two ways.
Algebra:
Geometry: — always the same number
= × the shadow of on
Angle between Two VectorsalgebraExample 2.23
(a)
1.88 rad
(b)
Angle between and , in radians.
rad
Angle between Two VectorsbridgeLab
Try Ex 2.23b and Ex 2.24: a right-angle mark appears. Same way gives cos θ = 1; opposite gives −1.
Angle between Two Vectorsalgebraproof · Theorem 2.4
law of cosines
properties iv, ii, i
□
Angle between Two Vectorsalgebrawhy arccos always works
a parabola that never dips below zero
:
Equality only for parallel vectors; the proof works in any number of components.
LO 2.3.2Determine whether two given vectors are perpendicularbridgeFigure 2.46
Turn (length 2.5) away from ; at 60° its shadow on points forward.
90°: no shadow,
120°: shadow backward, negative
180°: , the most negative,
LO 2.3.2Determine whether two given vectors are perpendicularbridgeTheorem 2.5
Example 2.24: Are and orthogonal?
: orthogonal
For which is ?
Angle between Two Vectorsalgebraproof · Theorem 2.5
(⇒)
(⇐)
"Nonzero" is essential: for every .
LO 2.3.3Find the direction cosines of a given vectorbridge
Example 2.25: Find the direction angles of , .
, 1.130 rad
0.877 rad
: the direction cosines are the unit vector .
Angle between Two VectorsalgebraCheckpoint 2.25
Checkpoint 2.25: Find the direction angles of , .
1.04 rad
2.58 rad — obtuse
1.40 rad
Angle between Two VectorsbridgeLab
, , always fill the bar.
LO 2.3.4Explain what is meant by the vector projection of one vector onto another vector, and describe how to compute itbridge
Drag the head of and project it onto .
Drop a perpendicular from the head of to the line of .
Shadow length
× unit vector → the projection vector
ProjectionsalgebraExample 2.27a
Example 2.27a: Project onto .
Shadow length
ProjectionsalgebraExample 2.27b
Example 2.27b: Project onto .
: obtuse
Same line as u; the sign picks the direction.
LO 2.3.4Explain what is meant by the vector projection of one vector onto another vector, and describe how to compute itbridge
Resolve into parts along and perpendicular to .
,
ProjectionsalgebraExample 2.28
Example 2.28: Resolve along .
:
along
ProjectionsbridgeLab
Drag the tips. Perpendicular: no shadow. Obtuse: the shadow points backward.
Projectionsalgebrawhy the formula
:
Lowest at , value
The shortest path to a line meets it at a right angle.
ProjectionsgeometryExample 2.29
Example 2.29: A ship's engine drives it at 20 knots on a course 15° N of E; a 2-knot current flows NE, 30° off the course.
Along the course: 21.73 knots
Same ship, current toward the southeast (60° off).
knots
LO 2.3.5Calculate the work done by a given forcebridge
A child pulls a wagon 50 ft with 8 lb on the handle at 55°. Find the work done.
Along the ground: lb
229 ft·lb
not
WorkalgebraExample 2.30
Example 2.30: N moves a suitcase from to m. Find the work.
37 J
30 lb at 60° pulls a handcart 10 ft.
ft·lb
LO 2.3.5Calculate the work done by a given forcegeometry
An 8 lb pull moves a wagon 50 ft; change the angle of the pull. At 0°: ft·lb
55°: ft·lb
90°: 0 — a pull across the motion does no work
120°: ft·lb — the force takes energy out
WorkbridgeLab
Try θ = 0°: 400 ft·lb. θ = 90°: none. Past 90°: negative, the force takes energy out. Checkpoint 2.29: 30 lb at 60° for 10 ft, 150 ft·lb.
§2.3wrap-up · self-check
| Objective | Takeaways; say them first, then click |
|---|---|
| 2.3.1 Calculate the dot product of two given vectors. | , a number; rules of multiplication, |
| 2.3.2 Determine whether two given vectors are perpendicular. | ; sign: acute, right, obtuse; nonzero: |
| 2.3.3 Find the direction cosines of a given vector. | ; squares add to 1 |
| 2.3.4 Explain and compute the vector projection. | the shadow ; , |
| 2.3.5 Calculate the work done by a given force. | ; zero at 90°, negative beyond |
| Mistake | Result | Fix |
|---|---|---|
| a vector where a number belongs | add the products | |
| Not dividing by the lengths | in Example 2.23(a) | |
| Mixing radians and degrees | "1.88°" for Example 2.23(a) | 1.88 rad = 107.98° |
| for in (2.6) | the shadow times too long | (2.6) has the square; (2.7) does not |
| for | a vector along the wrong line | the subscript is the line projected onto |
| Endpoint for displacement | in Example 2.30 | : 37 J |
| sin for work | ft·lb | θ is measured from the motion: cos, 229 |
| a vector dotted with a number | only makes sense | |
| ", so one is " | number rules applied to vectors | zero means perpendicular |
Exercises from p145; the book's key: p834–835, p840.
| # | task | answer |
|---|---|---|
| 2.21 | ||
| 2.22 | : ; | ; 53 |
| 2.23 | angle between | rad |
| 2.24 | x with | |
| 2.25 | direction angles of | rad |
| 2.26 | AAA in June: new prices and quantities | sales $15,685.50; profit $14,073.15 |
| 2.27 | along | |
| 2.28 | Example 2.29 with the current southeast | knots |
| 2.29 | 30 lb at 60°, 10 ft | ft·lb |
| # | task | answer | key step |
|---|---|---|---|
| 123 | (p145) | 6 | two terms in the plane |
| 125 | 0 | perpendicular | |
| 127 | , for | ; | number first, then scale |
| 131 | angle, | 2.82 rad; not acute | |
| 133 | angle, | ; acute | |
| 137 | angle, | ||
| 143 | orthogonal? (p146) | no (−5) | Theorem 2.5 |
| 149 | α with | ||
| 153 | angle A in triangle | 68.33° | , lengths 13 and 5 |
| 161 | direction cosines and angles of (p147) | ; 48°, 48°, 71° | divide by |
| 167 | , : | ; | (2.6) and (2.7) |
| 171 | decompose along | , check | |
| 173 | methane: distance PR; bond angle between | ; 109.47° | |
| 175 | work, N from to m (p148) | 17 N·m | |
| 177 | 25 lb at 20°, 50 ft | 1175 ft·lb |
Stretch: Exercise 179, a 500-lb wind at N30°E on a boat sailing north 100 ft: ft·lb.